101 x 50 = 5050. Reasoning: each number from 1 through 49 can be paired with another number between 51 and 100 to add to 101: 1+100, 2+99, 3+98, etc. There are 49 such pairs, and the number 50 adds one more, so that the sum is 101 X 50.
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There are two ways to solve this problem: You may notice that if you take away 100 from the series and add the smallest and largest number (1 + 99), you get 100. Then if add the next numbers in (2 + 98), you also get 100. Soon, you see a pattern. 3 + 97 = 100, 4 + 96 = 100 and so on. If you do this all the way to 50, you get 100, forty-nine time or 49*100 which 4900. You then add the 100 you took away earlier and add that to 4900 to get 5000. Lastly, because there is only one 50 in 1 to 100, it stays as 50 and you add that to 5000 to get the answer: 5050. The second way is to use the summation equation. This only works if you are starting from 1 and adding all the consecutive numbers to a certain number, say n. The equation is n(n+1)/2 where "n" is the final number in the series which in this case is 100. So 100(100+1)/2 = 100(101)/2 = 10100/2 = 5050.
104
There are 25 of them. Here's an easy way to find them:-- Write down all the numbers from 1 to 100.-- Cross out all the even numbers except '2'.-- Cross out all the numbers with digits that add up to a multiple of '3', except '3'.-- Cross out all the numbers that end in '5', except '5'.-- Cross out any others that can be divided evenly by any number other than '1' and themselves.-- The 25 remaining numbers are the primes you're looking for.I told you it was easy !
you could multiply 84 by 10 = 840 then multiply 84 by 2 = 168 add these two numbers = 1008