That problem can be set up in the following equation: 2x-8=40
First, add 8 to both sides to make get the x term alone. Then, divide by 2 to solve for x.
The answer ends up to be 24
The number works out as 14
2n-4
To solve the equation "Eight less than twice a number is fourteen," we can express it mathematically as ( 2x - 8 = 14 ), where ( x ) is the number. Adding 8 to both sides gives ( 2x = 22 ). Dividing both sides by 2 results in ( x = 11 ). Therefore, the number is 11.
Let the number be represented by ( x ). According to the problem, if the sum of the number and five is tripled, it can be expressed as ( 3(x + 5) ). This is equal to eight less than twice the number, or ( 2x - 8 ). Setting up the equation, we have ( 3(x + 5) = 2x - 8 ). Solving this gives ( x = -1 ).
That problem can be set up in the following equation: 2x-8=40 where 'x' represents the "number".First, add 8 to both sides to make get the x term alone. Then, divide by 2 to solve for x.The answer ends up to be 24.
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6
The number works out as 14
The number is 32 because (2*32) -8 = 56
Twenty more than twice a number is 52
2n-4
Let the number be x Twice a number means 2x 7 less than twice a number means 2x-7
The number is 40
Let 'x' represent "the number": 2x - 7 = -147 Solving: 2x = -140 x = -70
That problem can be set up in the following equation: 2x-8=40 where 'x' represents the "number".First, add 8 to both sides to make get the x term alone. Then, divide by 2 to solve for x.The answer ends up to be 24.
2n - 8 < 5n + 10 -3n < 18 n < -6
11