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if the two events are independent of each other:

(0.45)$55,000 + (0.3)$40,000 + (0.15)$15,000 + $0 = $34,500

This was achieved by adding the expected amount received each of the four outcomes: both receptions((0.6*0.75)(15,000+40,000) = 0.45($55,000), Either outcome ( 0.6(1-0.75)($15,000) or 0.75(1-0.6)($40,000)) and neither outcome((1-0.6)(1-0.75)(0)).

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Q: Estimation that there is 0.6 probability of receiving Rs 15000 due from A and 0.75 probability of receiving Rs 40000 due from B. What is the expected cash flow from these two accounts?
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