Here is one way to prove it. It is easier if the decagon is convex but the proof is valid even if not.
Take any point P in the plane. Again, it is easier if this point is inside the decagon but the proof is valid even if it is not.
Join all the vertices of the decagon to this point. So now you have ten triangles with a common vertex P.
The angles of these ten triangles form the internal angles of the decagon plus all the angles around P.
So the sum of the internal angles of the decagon is equal to the sum of the internal angles of all ten triangles with P as their common vertex minus the 360 degrees worth of angles at P itself.
The sum of the interior angles of each triangle is 180 degrees so the sum of ten triangles with common vertex P is 180*10 = 1800 degrees.
So the internal angles of the decagon add to 1800 - 360 = 1440 degrees.
Chat with our AI personalities
Supplementary angles are two angles that add up to 180 degrees. They are only equal if they both equal 90 degrees.
They are both 4 equal sided quadrilaterals with opposite parallel sides but a square has 4 equal interior angles of 90 degrees whereas a rhombus has 2 equal opposite acute angles and 2 equal opposite obtuse angles.
They work out as two equal opposite angles of 120 degrees and two equal opposite angles of 60 degrees.
No. The sum of the angles in ALL triangles is equal to 180 degrees. No triangle's angles equal 360.
No because they equal 180 degrees