220 deg K = -63.7 def F
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K = 5/9 (° F - 32) + 273 where K is a temperature in Kelvin, F is a temperatue in Fahrenheit . K = 5/9 (143.1 - 32) + 273 K = 334.722. i.e. 143.1 ºF = 334.722 K --- Also you can use the online calculator: http://www.metric-conversions.org/temperature-conversion.htm
The temperature 45°F is about 280.37 K K = 5/9 (F-32) + 273.15 This is the Celsius temperature plus 273.15, the offset from 0 K to 0°C 45°F = about 7.22°C, which plus 273.15 is 280.37 kelvins
0 K is equal to -459.67 °F The theoretical temperature "absolute zero" is 0 K, -273.15 °C, or -459.67 °F. 0°K = -459.67°F = -273.15 °C
They are all the same temperature, i.e. the boiling point of water at standard pressure.Except the "100 f" should be "100 c".
Internationally agreed temperature scales are based on fixed points and interpolating thermometers. The most recent official temperature scale is the International Temperature Scale of 1990. It extends from 0.65 K (−272.5 °C; −458.5 °F) to approxim Internationally agreed temperature scales are based on fixed points and interpolating thermometers. The most recent official temperature scale is the International Temperature Scale of 1990. It extends from 0.65 K (−272.5 °C; −458.5 °F) to approximately 1,358 K (1,085 °C; 1,985 °F). ately 1,358 K (1,085 °C; 1,985 °F).