(c + 2)(c + 2) or (c + 2)2
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c2 + 4c + 4 =(c + 2) (c + 2)= (c + 2)2
4(a + 2b - 4c)
C2-4c+4=0 (c-2)(c-2) c-2=0 and c-2=0 C=2 and c=2 Put 2 in place of c and solve the equation
4c+1-5+2c = 6c-4.
2. c2 + c2 + 8 = 8c 2c2 - 8c + 8 = 0 c2 - 4c + 4 = 0 (c - 2)(c - 2) = 0 (c - 2)2 = 0 c - 2 = 0 c = 2