n3 + 3n2 + 4n + 12 = (n3 + 3n2) + (4n + 12)
= n2(n + 3) + 4(n + 3)
= (n2 + 4)(n + 3).
-4n3 + 8n2 - 4n + 7
Given any number it is easy to find a rule based on a polynomial of order 4 such that the four numbers are as listed in the question and the next is the given number. There are also non-polynomial solutions.The polynomial with the lowest order for this sequence isUn = -3n2 + 14n + 64 for n = 1, 2, 3, ...and, accordingly, the next number is 59.
3n2-8n+4 = (3n-2)(n-2) when factored
3
The GCF is 3n.
(3n+2)(n+1)
-((3n - 1)(n + 3))
The factors of 6 are 1, 2, 3, 6. For them to be common, they need to be compared to another set of factors.
-4n3 + 8n2 - 4n + 7
Given any number it is easy to find a rule based on a polynomial of order 4 such that the four numbers are as listed in the question and the next is the given number. There are also non-polynomial solutions.The polynomial with the lowest order for this sequence isUn = -3n2 + 14n + 64 for n = 1, 2, 3, ...and, accordingly, the next number is 59.
3n2-8n+4 = (3n-2)(n-2) when factored
Given ANY number is it easy to find a polynomial of order 5 that will fit the five given numbers and the selected sixth. However, the simplest polynomial to fit the above numbers is Un = (3n2 - 3n + 4)/2 for n = 1, 2, 3, ... Accordingly, the next number is 47.
Is it a. 3n square and 3n ans. 3n b. 3n *2 and 3n ans.3n ans. 3n for both!!
so 3n2 = 15 ie n2 = 5 so n = sqrt 5
3
Formula: (Hg2)3N2
2NaN ---> 2Na + 3N2