Begin by noticing that your factor pairs will have the form ( __x + __)(__x - __). Remember that the two ends are products, and the middle number is a sum. Find the factor pairs for each end number. 4 3 1 and 4 1 and 3 2 and 2 Since 3 only has one option, you know either: ( __x + 1)(__x - 3) or (__x - 1)(__x + 3) then start testing the factor pairs of 4. I like to start with the closest together pair - 2 and 2 here. Do 2 x 1 and 2 x 3 subtract to give you 4? Yes! 6 - 2 = 4! So I want the 6 positive and the 2 negative. This gives me (2x + 3)(2x - 1). Check your answer if you are unsure.
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Take out the common factor, which in this case is 4x2. Divide each of the terms by this common factor. 12x2 - 4x3 = 4x2(3+x)
4x3+10x2+2x+5= (2x+5)(2x2+1)
Start with 4 and keep multiplying it. Maybe start with 4x1 then 4x2 then 4x3 etc. You have 4,8,12, etc.
Answer this question…A. x4 + 2x3 + 9x2 + 4 B. x4 + 4x3 + 9x2 + 4 C. x4 + 2x3 + 9x2 + 4x + 4 D. x4 + 2x3 + 9x2 - 4x + 4
4x3=12 250-12=238 238/50=4.76