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2x² - 18
Looking at it, you know that the first factors in each set are 2x and x.
(2x ± ?) (x ± ?)
Then guess and check to find 2 factors that when multipled together equal -18, but when plugged into the equation make the original statement true. In this case 6 and 3, however one or the other needs to be negative.
(2x + 6)(x - 3) OR (2x - 6)(x + 3)
Multiply it out to check your answer:
(2x + 6)(x - 3) = 2x² - 6x + 6x - 18
2x² - 6x + 6x - 18 = 2x² - 18
You would get the same result with (2x - 6)(x + 3)
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we factorise a number by finding the common factor. example: 2x+6 = 2 is the common factor the 2 is then put outside the bracket 2x+6 = 2(x+3)
Factorise 2x plus 7 plus 5?
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5x4 - 2x = x*(5x3 - 2) and that cannot be factorised further without invoking surds.
What is 2x -2?
4
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