2x² - 18
Looking at it, you know that the first factors in each set are 2x and x.
(2x ± ?) (x ± ?)
Then guess and check to find 2 factors that when multipled together equal -18, but when plugged into the equation make the original statement true. In this case 6 and 3, however one or the other needs to be negative.
(2x + 6)(x - 3) OR (2x - 6)(x + 3)
Multiply it out to check your answer:
(2x + 6)(x - 3) = 2x² - 6x + 6x - 18
2x² - 6x + 6x - 18 = 2x² - 18
You would get the same result with (2x - 6)(x + 3)
To factorise the expression (10x^2 - 15xy), first identify the common factors in both terms. The common factor is (5x). Factoring this out, we get: [ 10x^2 - 15xy = 5x(2x - 3y) ] Thus, the factorised form is (5x(2x - 3y)).
we factorise a number by finding the common factor. example: 2x+6 = 2 is the common factor the 2 is then put outside the bracket 2x+6 = 2(x+3)
2x + 7 + 5 = 2x + 12 = 2*x + 2*6 = 2*(x+6)
5x4 - 2x = x*(5x3 - 2) and that cannot be factorised further without invoking surds.
To factor the expression (2x^2 + 6x - 13), we can look for two numbers that multiply to (2 \times -13 = -26) and add to (6). These numbers are (13) and (-2). Rewriting the expression, we have (2x^2 + 13x - 2x - 13) which can be grouped and factored as ((2x - 1)(x + 13)). Thus, the factorization of the expression is ((2x - 1)(x + 13)).
If you mean: 2x+10 then it is 2(x+5)
2x + 6 = 2(x+3)
To factorise the expression (10x^2 - 15xy), first identify the common factors in both terms. The common factor is (5x). Factoring this out, we get: [ 10x^2 - 15xy = 5x(2x - 3y) ] Thus, the factorised form is (5x(2x - 3y)).
we factorise a number by finding the common factor. example: 2x+6 = 2 is the common factor the 2 is then put outside the bracket 2x+6 = 2(x+3)
2x + 12 = 2*x + 2*6 = 2*(x + 6)
2x + 7 + 5 = 2x + 12 = 2*x + 2*6 = 2*(x+6)
It is 2(2x+3) when factorised
5x4 - 2x = x*(5x3 - 2) and that cannot be factorised further without invoking surds.
To factor the expression (2x^2 + 6x - 13), we can look for two numbers that multiply to (2 \times -13 = -26) and add to (6). These numbers are (13) and (-2). Rewriting the expression, we have (2x^2 + 13x - 2x - 13) which can be grouped and factored as ((2x - 1)(x + 13)). Thus, the factorization of the expression is ((2x - 1)(x + 13)).
2 + 2x = 18 2x = 18 - 2 2x = 16 x = 8
4
2(2x-11)(3x+5)