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What are the prime factors of 720 using exponents?
24 x 32 x 5 = 720
How the you get the multiplication maze of 720?
As a product of its prime factors: 2*2*2*2*3*3*5 = 720 or as 24*32*5 = 720
What are the common factors of 504 and 720?
The common factors of 504 and 720 are 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36 and 72.
What do all 16 12 9 and 10 all go into?
This is a "least common multiple (LCM)" question in disguise. The prime factors of 16 are 2, 2, 2 and 2 The prime factors of 12 are 2, 2, and 3 The prime factors of 9 are 3 and 3 The prime factors of 10 are 2 and 5 So, the least common multiple (and any multiple) will have to have factors of * four 2s * two 3s * one 5 (2 x 2 x 2 x 2) x (3 x 3) x 5 = 16 x 9 x 5 = 720 To prove our findings * 720 ÷ 16 = 45 * 720 ÷ 12 = 60 * 720 ÷ 9 = 80 * 720 ÷ 10 = 72 These numbers will also evenly divide into any multiple of 720, such as 1,440, 2,160, 2,880 etc.
What 3 numbers multiplied get 720?
Well, isn't that a happy little math problem! To find three numbers that multiply to 720, we can start by breaking down 720 into its prime factors: 2 x 2 x 2 x 3 x 3 x 5. Then, we can group these factors into three numbers, like this: 2 x 2 x 180, which equals 720. So, the three numbers are 2, 2, and 180.
