Just multiply the following: 111 x 1 111 x 2 111 x 3 etc.
It depends on the base used for 111. But guessing that binary is implied, it would represent seven: (1 x 2²) + (1 x 2¹) + (1 x 2º) = (1 x 4) + (1 x 2) + (1 x 1) = 4 + 2 + 1 = 7.
There are some operators missing that make this rather ambiguous. If you mean: 3x - 111 + x2 = x and wish to solve for x, then here's the answer: x2 + 2x - 111 = 0 x2 + 2x + 1 = 112 (x + 1)2 = 112 x + 1 = ± √112 x = -1 ± 4√7 If you mean: 3x - 111 = x2 + x Then solving for x gives us this: x2 - 2x + 111 = 0 x2 - 2x + 1 = 112 (x - 1)2 = 112 x - 1 = ± √112 x = 1 ± 4√7 If you mean: 3x - 111 + x2 + x And want to simplify it, that would be: x2 + 4x - 111 Not much really, as it can't be factored further.
111 = 111 x 1 100 = 1 x 100 110 = 11 x 10 ----- 321 = total
666
Just multiply the following: 111 x 1 111 x 2 111 x 3 etc.
It depends on the base used for 111. But guessing that binary is implied, it would represent seven: (1 x 2²) + (1 x 2¹) + (1 x 2º) = (1 x 4) + (1 x 2) + (1 x 1) = 4 + 2 + 1 = 7.
222 x 1 111 x 2 444 x (1/2)
There are some operators missing that make this rather ambiguous. If you mean: 3x - 111 + x2 = x and wish to solve for x, then here's the answer: x2 + 2x - 111 = 0 x2 + 2x + 1 = 112 (x + 1)2 = 112 x + 1 = ± √112 x = -1 ± 4√7 If you mean: 3x - 111 = x2 + x Then solving for x gives us this: x2 - 2x + 111 = 0 x2 - 2x + 1 = 112 (x - 1)2 = 112 x - 1 = ± √112 x = 1 ± 4√7 If you mean: 3x - 111 + x2 + x And want to simplify it, that would be: x2 + 4x - 111 Not much really, as it can't be factored further.
1 x 111 = 111
The power is 1. 2 x 7 x 11 = 21 x 71 x 111 or (2 x 7 x 11)1
IF 3X-1=11, WHAT IS THE VALUE OF X 2 + X?
111 is not a prime number. You can multiply 3 x 37 and 1 x 111 to get 111.
Well i see 2 answers 1 x 1 x 1 = 1 and 1 x 1 x 1 = 111 right answers is 1
1 x 111, 3 x 37.
111 = 111 x 1 100 = 1 x 100 110 = 11 x 10 ----- 321 = total
222 = 1 x 222, 2 x 111, 3 x 74, 6 x 37.