0.8664
To find the correlation coefficient ( r ), use the formula: [ r = \frac{n \cdot \Sigma x_i y_i - \Sigma x_i \cdot \Sigma y_i}{\sqrt{(n \cdot \Sigma x_i^2 - (\Sigma x_i)^2)(n \cdot \Sigma y_i^2 - (\Sigma y_i)^2)}} ] Given ( n = 15 ), ( \Sigma x_i = 1293 ), ( \Sigma y_i = 48.58 ), ( \Sigma x_i y_i = 4226.2 ), ( s_x = 6.9714 ), and ( s_y = 0.4236 ), first calculate ( \Sigma x_i^2 ) and ( \Sigma y_i^2 ) using the relation ( s_x^2 = \frac{\Sigma x_i^2}{n} - \left(\frac{\Sigma x_i}{n}\right)^2 ) and ( s_y^2 = \frac{\Sigma y_i^2}{n} - \left(\frac{\Sigma y_i}{n}\right)^2 ). After obtaining these values, substitute them into the formula for ( r ) to find the correlation coefficient.
It's just rock and roll...
15 plus -3 equals 12 12 divided by -6 equals -2
21
12
It's just rock and roll...
If the question is to do with a probability distribution curve, the answer is ONE - whatever the values of mu and sigma. The area under the curve of any probability distribution curve is 1.
12/15 equals 0.8
15 plus -3 equals 12 12 divided by -6 equals -2
661
To find the percentage of 12 out of 15, you would first divide 12 by 15 to get 0.8. Then, multiply 0.8 by 100 to convert it to a percentage, which equals 80%. Therefore, 12 out of 15 is 80% as a percentage.
3/5 = 9/15 and is not equal to 12/15
180 divided by 12 is 15.
21
12
12-3y = 15 -3y = 15-12 -3y = 3 y = -1
To find 3/12 of 60, first simplify 3/12 to 1/4. Then, multiply 60 by 1/4, which equals 15. Therefore, 3/12 of 60 is 15.