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To find square root of a nos without using built in function?
/*Java program to find out square root of a given number * without using any Built-In Functions */ public class SquareRootDemo2 { public static void main(String[] args) { //Number for which square root is to be found double number = -12; //This method finds out the square root findSquareRoot(number); } /*This method finds out the square root without using any built-in functions and displays it */ public static void findSquareRoot(double number) { boolean isPositiveNumber = true; double g1; //if the number given is a 0 if(number==0) { System.out.println("Square root of "+number+" = "+0); } //If the number given is a -ve number else if(number<0) { number=-number; isPositiveNumber = false; } //Proceeding to find out square root of the number double squareRoot = number/2; do { g1=squareRoot; squareRoot = (g1 + (number/g1))/2; } while((g1-squareRoot)!=0); //Displays square root in the case of a positive number if(isPositiveNumber) { System.out.println("Square roots of "+number+" are "); System.out.println("+"+squareRoot); System.out.println("-"+squareRoot); } //Displays square root in the case of a -ve number else { System.out.println("Square roots of -"+number+" are "); System.out.println("+"+squareRoot+" i"); System.out.println("-"+squareRoot+" i"); } } }
What is the number of pieces of string you can get by using 16 cuts to cut apart a straight piece of string?
the normal amount would be 17
How do you find the side of the square when the diagnol is given?
By using Pythagoras' theorem.
A prime number between 10 and 20 one more than a square number?
17The prime numbers between 10 and 20 are 11, 13, 17 and 19. There is only one square number between 10 and 20: 16. Using the criteria given, the number that fits is 17.
What does Term mean when using square and triangle numbers?
Each term is a square or triangular number. In the context of the sequence of square numbers, the first term is the first square number, the second term is the second square number and so on.
