Any number that is a multiple of 60 would be divisable by all of those numbers.
ex. 120, 600, 660, 5460, 6000, 9960
Every three-digit number that ends with a zero or a 5 is divisible by 5.It doesn't matter what the first 2 digits are.
Any multiple of 36 will do. Multiply 36 by different numbers, until you get a 5-digit number.Any multiple of 36 will do. Multiply 36 by different numbers, until you get a 5-digit number.Any multiple of 36 will do. Multiply 36 by different numbers, until you get a 5-digit number.Any multiple of 36 will do. Multiply 36 by different numbers, until you get a 5-digit number.
Some numbers that are divisible by 63 is 1,3,7,9, and 21.
numbers that are divisible by 4 is either: 4n or numbers in which the number formed by last two digits are divisible by 4
925 is a number divisible by 5, as its last digit is a 5. It is an odd number. Its divisors are 5, 5, and 37, also all odd numbers. It is a three-digit number.
50% of numbers divisible by 5 are even, the other 50% are odd. If the single's digit of a number is 5, then the number is divisible by 5 and odd. For example, 25. However, if the single's digit of a number is 0, then the number is divisible by 5 and even. For example, 20.
Every three-digit number that ends with a zero or a 5 is divisible by 5.It doesn't matter what the first 2 digits are.
Here are some of them: 10,010 10,021 10,032 and 10,043.
All 2 digit numbers are divisible by 7: it is simply that some of the quotients are not whole numbers. 10/7 = 1 3/7 99/7 = 14 1/7 So the number of 2-digit numbers which are evenly divisible by 7 are 14-1 = 13.
All numbers divisible by 9 are divisible by 3, so you want all multiples of 9 that are 5 digit numbers. 10000 ÷ 9 = 11111/9 → first multiple of 9 that is a 5 digit number is 1112 x 9 = 10008 100000÷ 9 = 111111/9 → last multiple of 9 that is a 5 digit number is 11111 x 9 = 99999 → there are 11111 - 1112 + 1 = 10,000 five digit numbers that are divisible by 9 (and 3). I'll let you work some out (hint: multiple any number between 1112 and 11111 inclusive by 9).
Some numbers are divisible by 2 and Some are not.
Any multiple of 36 will do. Multiply 36 by different numbers, until you get a 5-digit number.Any multiple of 36 will do. Multiply 36 by different numbers, until you get a 5-digit number.Any multiple of 36 will do. Multiply 36 by different numbers, until you get a 5-digit number.Any multiple of 36 will do. Multiply 36 by different numbers, until you get a 5-digit number.
Some numbers that are divisible by 63 is 1,3,7,9, and 21.
-4
First we need to find the L.C.M. of 40, 48 and 60. 40 = 2x2x2x5 48 = 2x2x2x2x3 60 = 2x2x3x5 After taking out common factors, we have L.C.M. = 2x2x2x3x5x2 = 240 To find the greatest 4 digit number which is divisible by 240 we divide 9999 by 240. Remainder = 159 Subtracting this remainder from 9999 we get 9999 - 159 = 9840. So, the required answer is 9840.
numbers that are divisible by 4 is either: 4n or numbers in which the number formed by last two digits are divisible by 4
925 is a number divisible by 5, as its last digit is a 5. It is an odd number. Its divisors are 5, 5, and 37, also all odd numbers. It is a three-digit number.