C = ~251.33 meters.
The perimeter is 40m
360
0.0254 m = 1 in (exactly) → 40m = 40 ÷ 0.0254 in ≈ 1574.8 in
40 metersFormula: Area = side2side = square root of Area = √100 = 10mPerimeter = 4 * side = 4 * 10m = 40m
Multiply 40 by the value of Pi and you have your answer.
C = ~251.33 meters.
40m
The perimeter is 40m
40m
360
To calculate the volume of a rectangular prism, you multiply the length, width, and height. 40m × 40m × 60m = 96, 000 m3.
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0.0254 m = 1 in (exactly) → 40m = 40 ÷ 0.0254 in ≈ 1574.8 in
40 metersFormula: Area = side2side = square root of Area = √100 = 10mPerimeter = 4 * side = 4 * 10m = 40m
5m*8m = 40m/2=20 20 is your answer
As two dimensions of the park are given, it can be assumed to be a rectangle in shape. → perimeter of fence = 40m + 30m + 40m + 30m = 140m For the area of the path, it runs along all the perimeter of the fence so its length is 140m and its width is 1.5m → the area of the footpath next to the fence is 140m x 1.5m = 210 m2. However, this area only includes the footpath that has one side next to the fence but excludes those parts of the footpath that go round the corners of the fence. As the path is given as 1.5m wide, it could be assumed that the path at each of the corners will be a quarter circle of radius 1.5m. As there are four of these quarter circles, their total area is the area of a whole circle: → area of the path = 210m2 + π x (1.5m)2 = 140m2 + 2.25π m2 ≈ 217.07 m2 The corners could also be squared off, so that each is a square of side 1.5m: → area of the path = 210m2 + 4 x (1.5m)2 = 219 m2.