The coefficient of ((x + y)^{20}) can be found using the binomial theorem, which states that ((a + b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k). In this case, the coefficient of each term in the expansion is given by (\binom{20}{k}), where (k) is the exponent of (y) and (n-k) is the exponent of (x). The specific coefficient for any term ((x^a y^b)) can be determined by choosing (a) and (b) such that (a + b = 20). For the overall expansion, the sum of the coefficients for all terms is (2^{20}).
The coefficient of X is 1
1
4y20 = 500 => y20 = 25 => y = 20√25 = 1.1746 approx Then x = 500 - y = 489.8254 (approx).
1
the coefficient of any x term in the absence of any other number is 1. ax + bx + c is the form.
The coefficient of X is 1
1
The coefficient is 6.
The only coefficient here is just 1
4y20 = 500 => y20 = 25 => y = 20√25 = 1.1746 approx Then x = 500 - y = 489.8254 (approx).
1
the coefficient of any x term in the absence of any other number is 1. ax + bx + c is the form.
The are none because the coefficient of a term is the number in front of the variable as for example 3x whereas 3 is the coefficient and x is the variable and 3x means 3 times x
48
The 4.
x^2 plus 16y?
Five is the coefficient of x.