Factors of 25: 1, 5, 25 Their sum = 31 Difference between 31 and 8 = 23.
155, 310, 465 are all divisible by both 5 and 31. Keep adding 155 to find more numbers divisible by both 5 and 31.
31/5 - 9/5 = 22/5 = 4 and 2/5
5-3=2 Difference is sometimes used to mean "subtract this from that"
x+x+5 = 31 x+x = 31-5 2x = 26 x = 13
Factors of 25: 1, 5, 25 Their sum = 31 Difference between 31 and 8 = 23.
155, 310, 465 are all divisible by both 5 and 31. Keep adding 155 to find more numbers divisible by both 5 and 31.
31/5 - 9/5 = 22/5 = 4 and 2/5
5-3=2 Difference is sometimes used to mean "subtract this from that"
x+x+5 = 31 x+x = 31-5 2x = 26 x = 13
7
62
5 31 as a decimal = 0.16135/31:= 5 ÷ 31= 0.1613 in decimal
2 x 5 x 31 = 310
5 as a percentage of 31 = 100*5/31 = 16.13%, approx.
5 X 31 = 155.
Difference is 5,7,9,11,13 Second difference is 2 (2x)^2 gives 4,9,16,25 Difference between 2x^2 and sequence is -5 Thus, the nth term will be (2n)^2-5