Q: Find the difference of 31 and 5?

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Factors of 25: 1, 5, 25 Their sum = 31 Difference between 31 and 8 = 23.

155, 310, 465 are all divisible by both 5 and 31. Keep adding 155 to find more numbers divisible by both 5 and 31.

31/5 - 9/5 = 22/5 = 4 and 2/5

5-3=2 Difference is sometimes used to mean "subtract this from that"

x+x+5 = 31 x+x = 31-5 2x = 26 x = 13

Related questions

Factors of 25: 1, 5, 25 Their sum = 31 Difference between 31 and 8 = 23.

155, 310, 465 are all divisible by both 5 and 31. Keep adding 155 to find more numbers divisible by both 5 and 31.

31/5 - 9/5 = 22/5 = 4 and 2/5

5-3=2 Difference is sometimes used to mean "subtract this from that"

x+x+5 = 31 x+x = 31-5 2x = 26 x = 13

7

62

5 31 as a decimal = 0.16135/31:= 5 ÷ 31= 0.1613 in decimal

2 x 5 x 31 = 310

5 as a percentage of 31 = 100*5/31 = 16.13%, approx.

5 X 31 = 155.

Difference is 5,7,9,11,13 Second difference is 2 (2x)^2 gives 4,9,16,25 Difference between 2x^2 and sequence is -5 Thus, the nth term will be (2n)^2-5