how do i find the median of a continuous probability distribution
You multiply the probability by 100.
10.56% The probability that he misses his first shot is 12%. The probability that he makes the second shot is 88%. The probability of missing the first shot and making the second shot is 12% * 88%, or 0.12*0.88*100.
Missing....? But the answer to find the missing is normally either "algebra" or "find another equation to use."
Read the introduction to probability and probability measures at StatLect.com
8=D
Try the link below.
Share If each quadrilateral below is a rhombus, find the missing measures UV: 8 and WX=5?
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Pls help
A=14,b=8
You can find the answer you want, below, a link to Table : Gadgets - Google Docs Help.
how do i find the median of a continuous probability distribution
Please rephrase your question. An array usually has a fixed size and I don't recall ever having to "go below its size". This implies that the missing elements are not within the range of the array.
You multiply the probability by 100.
This is a binomial distribution; number of trials (n) is 6, probability of success (p) is 1/2 or 0.5. With this information you can go to a Binomial Distribution Table and find the solution. Within the section of values for n=6 and p=.5, read from the section the probability of 2 which is 0.2344 (see related link for table).
10.56% The probability that he misses his first shot is 12%. The probability that he makes the second shot is 88%. The probability of missing the first shot and making the second shot is 12% * 88%, or 0.12*0.88*100.