Probability is a number in the range [0, 1]. The question gives a probability (240) which is way outside this range and so is not valid.
the probability is 1 out of 6
0.63 = 0.216
To find the probability of getting heads on the first two flips and tails on the third flip when flipping three fair coins, we multiply the probabilities of each individual event. The probability of getting heads on a flip is 1/2, so for the first two flips, it is (1/2) * (1/2) = 1/4. The probability of getting tails on the third flip is also 1/2. Therefore, the overall probability is (1/4) * (1/2) = 1/8.
The probability is 8/36 or 2/9
Probability that the sum is 6 = 5/36 Probability that the sum is 7 = 6/36
the probability is 1 out of 6
First we find the probability of getting a 7. Of the 36 outcomes possible 6 result in a sum of 7, in other words 1/6. The probability of getting an 11 is 2/36 or 1/18. The probability of getting one or the other is the sum of the two, 8/36 or 2/9. The proability of getting neither is equal to the probability of getting anything other than 7 or 8. We find this value by subtracting 2/9 from 1. So the probability of not getting 7 or 11 is 7/9.
0.63 = 0.216
To find the probability of getting heads on the first two flips and tails on the third flip when flipping three fair coins, we multiply the probabilities of each individual event. The probability of getting heads on a flip is 1/2, so for the first two flips, it is (1/2) * (1/2) = 1/4. The probability of getting tails on the third flip is also 1/2. Therefore, the overall probability is (1/4) * (1/2) = 1/8.
The probability is 8/36 or 2/9
The probability is 1/6.
Probability that the sum is 6 = 5/36 Probability that the sum is 7 = 6/36
It is 1/8.
Assuming these are regular dice, the probability is 1.
To determine the probability of obtaining offspring with the genotypes JJQQ or Jjqq from a dihybrid cross between JjQq and JJQP, we first analyze each genotype separately. The probability of getting JJQQ from this cross is 1/4, while the probability of getting Jjqq is also 1/4. To find the total probability of getting either genotype, we sum these probabilities: 1/4 + 1/4 = 1/2. Thus, the probability of obtaining an offspring with genotype JJQQ or Jjqq is 1/2.
To find the probability of getting a sum of 9 from two throws of dice, we first identify the combinations that yield this sum: (3,6), (4,5), (5,4), and (6,3). There are 4 favorable outcomes. Since there are a total of 36 possible outcomes when rolling two dice (6 sides on the first die multiplied by 6 sides on the second), the probability is 4 out of 36. Simplifying this gives a probability of 1/9.
To find the probability of getting at least one head in 4 coin tosses, it's easier to calculate the complementary probability of getting no heads at all (i.e., getting all tails). The probability of getting tails in a single toss is 0.5, so for 4 tosses, the probability of all tails is ( (0.5)^4 = 0.0625 ). Therefore, the probability of getting at least one head is ( 1 - 0.0625 = 0.9375 ) or 93.75%.