Probability is a number in the range [0, 1]. The question gives a probability (240) which is way outside this range and so is not valid.
the probability is 1 out of 6
0.63 = 0.216
The probability is 8/36 or 2/9
Probability that the sum is 6 = 5/36 Probability that the sum is 7 = 6/36
Assuming these are regular dice, the probability is 1.
the probability is 1 out of 6
First we find the probability of getting a 7. Of the 36 outcomes possible 6 result in a sum of 7, in other words 1/6. The probability of getting an 11 is 2/36 or 1/18. The probability of getting one or the other is the sum of the two, 8/36 or 2/9. The proability of getting neither is equal to the probability of getting anything other than 7 or 8. We find this value by subtracting 2/9 from 1. So the probability of not getting 7 or 11 is 7/9.
0.63 = 0.216
The probability is 8/36 or 2/9
The probability is 1/6.
Probability that the sum is 6 = 5/36 Probability that the sum is 7 = 6/36
It is 1/8.
Assuming these are regular dice, the probability is 1.
To find the probability of getting a sum of 9 from two throws of dice, we first identify the combinations that yield this sum: (3,6), (4,5), (5,4), and (6,3). There are 4 favorable outcomes. Since there are a total of 36 possible outcomes when rolling two dice (6 sides on the first die multiplied by 6 sides on the second), the probability is 4 out of 36. Simplifying this gives a probability of 1/9.
To find the probability of getting at least one head in 4 coin tosses, it's easier to calculate the complementary probability of getting no heads at all (i.e., getting all tails). The probability of getting tails in a single toss is 0.5, so for 4 tosses, the probability of all tails is ( (0.5)^4 = 0.0625 ). Therefore, the probability of getting at least one head is ( 1 - 0.0625 = 0.9375 ) or 93.75%.
The probability is still 50%
If it is a fair die that is rolled once, then the probability is 2/3.