The graph of [ y = 4x + 2 ] is a straight line with a slope of 4.
Any line with a slope of 4 is parallel to that one, and any line parallel to that one has a slope of 4.
The graph of the equation [ x = -3 ] is a straight vertical line, passingthrough the point [ x = -3 ] on the x-axis. Its slope is infinite.
6
2y = 5x + 8Divide each side by 2:y = 2.5x + 4The slope of the graph is 2.5 .The y-intercept is 4.
This algebra lesson explains how to find the slope of a line by looking at its graph. To get from the point (-2, -1) to the point (4, 3), you rise up 4... and run 6.
An equation in the form y = mx + c has slope m and intercept c. y - 9 = 0.75x => y = 0.75x + 9 So slope = 0.75 and intercept = 9
find the constant of variation and the slope of the given line from the graph of y=2.5x
The graph of the equation [ x = -3 ] is a straight vertical line, passingthrough the point [ x = -3 ] on the x-axis. Its slope is infinite.
You find the slope of the tangent to the curve at the point of interest.
You can find the speed of an object from its distance-time graph by calculating the slope of the graph at a specific point. The slope represents the object's velocity at that particular moment. By determining the slope, you can find the speed of the object at that point on the graph.
6
2y = 5x + 8Divide each side by 2:y = 2.5x + 4The slope of the graph is 2.5 .The y-intercept is 4.
Use the four-step process to find the slope of the tangent line to the graph of the given function at any point.
The slope of the graph does not exist. And in the context of "this" problem it means absolutely nothing.
Find the slope of the tangent to the graph at the point of interest.
To find acceleration from a speed-time graph, you need to calculate the slope of the speed-time graph. The slope at any point on the speed-time graph represents the acceleration at that specific time. If the speed-time graph is linear, then the acceleration will be constant. If the speed-time graph is curved, you can find the acceleration by calculating the slope of the tangent line at a specific point.
To find resistance from a graph of voltage vs. current, you can calculate the slope of the graph. Resistance is equal to the slope, so you can divide the voltage by the current to determine the resistance. The unit of resistance is ohms (Ω).
Remember the standard form of an equation:Y = (slope) x + (y-intercept)Now take your equationY = (-1) x + (0)Compare yours to the standard one.That's how to find them.Now can you identify the slope and y-intercept of the graph of your equation ?