Slope of a line perpendicular to x-y=16
That's a vertical line; the slope is not defined.
-8y = x - 16 y = (-1/8)x + 2 The slope is -1/8
The equation for the slope of a line is y=mx+b
3X - 2Y = - 16 - 2Y = - 3X - 16 Y = (3/2)X + 8 ==============slope intercept form
Slope of a line perpendicular to x-y=16
That's a vertical line; the slope is not defined.
-8y = x - 16 y = (-1/8)x + 2 The slope is -1/8
The equation for the slope of a line is y=mx+b
3X - 2Y = - 16 - 2Y = - 3X - 16 Y = (3/2)X + 8 ==============slope intercept form
1.6x - 3.2y = 16 3.2y = 1.6x - 16 y = 0.5x - 5 So slope = coefficient of x = 0.5
The equation is -x -16 equals y. You find this by using the equation for a line mx plus b equals y, where 'm' is the slope and 'b' is the y-intercept. From the information given, you have two points which are 0.-16 ans -16,0. You can find 'm' the slope with the equation y2-y1/x2-x1, or -16-0/0- -16. This is -16/16 or -1 for m and the y-intercept is given as -16. So, substitute into the line equation these values to get the answer given.
The graph of the equation [ x = -3 ] is a straight vertical line, passingthrough the point [ x = -3 ] on the x-axis. Its slope is infinite.
It has infinite slope.
Convert the equation into standard form, y = mx + c, where m is the slope and c is the y intercept. -2x - 8y = 16 8y = -2x - 16 y = - x/4 - 2 Then the slope is -1/4 and the y intercept is -2
7x is still the slope, no matter what x equals.
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