-2-5
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y=x2-10x+30=(x-5)2-25+30=(x-5)2+5
You only need to find the vertex of a parabola, so I assume this is the equation. Y = X^2 - 10X + 25 set to 0 X^2 - 10X + 25 = 0 now, you need to complete the square. Halve the linear term (-10), square it and add that to both sides. subtract 25 from each side to start X^2 - 10X = - 25 X^2 - 10X + 25 = - 25 + 25 factor left; gather like terms right (X - 5)^2 = 0 Vertex (5,0)
You find x. Oh! There it is!! ^ See?
x + 13x + 10x = 50 - 6
x2 + 10x + 21 = (x + 3)(x + 7)