Find three consecutive even integers whose sum is -42?

Answer 1

Three consecutive even numbers can be expressed as (x) + (x + 2) + (x + 4), where x is the least of the three numbers. If these three add to 42 then it can be said that: (x) + (x + 2) + (x + 4) = 42 This leads to: 3x + 6 = 42, which results in 3x = 36. So x = 12. This means that numbers are 12, 12+2, and 12+4. The answer is 12, 14, and 16. To double check, 12 + 14 + 16 = 42.
n+(n+2)+(n+4)=42

3n+6=42

3n=36

n=12

12, 14, 16

Answer 2

The numbers are -16, -14 and -12.