Three consecutive even numbers can be expressed as (x) + (x + 2) + (x + 4), where x is the least of the three numbers. If these three add to 42 then it can be said that: (x) + (x + 2) + (x + 4) = 42 This leads to: 3x + 6 = 42, which results in 3x = 36. So x = 12. This means that numbers are 12, 12+2, and 12+4. The answer is 12, 14, and 16. To double check, 12 + 14 + 16 = 42.
n+(n+2)+(n+4)=42
3n+6=42
3n=36
n=12
12, 14, 16
The integers are 16, 17 and 18.
The integers are 19, 20 and 21.
Those three odd integers are 43, 45, and 47.
-9, -10 and -11.
They are -15, -14 and -13.
Find 2 consecutive ODD integers whose sum is -88 ANSWER: -45, -43
No. There is no set of three consecutive even integers with a sum of 40.
The integers are 16, 17 and 18.
The integers are 19, 20 and 21.
The integers are -37, -36 and -35. Also, using consecutive even integers: -38, -36 and -34.
Those three odd integers are 43, 45, and 47.
Those three odd integers are 43, 45, and 47.
The even integers are 22, 24 and 26.
99, 100, and 101
31, 32 and 33
-9, -10 and -11.
They are -15, -14 and -13.