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There are two consecutive odd integers whose sum is 176. They are 87 and 89.

Q: Find two consecutive integers whose sum is 176?

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87 and 89.

There are three consecutive integers. Let's call the middle one x. The one before it is x - 1 and the one after it is x + 1. Adding them together equals 3x. That means that whatever they equal has to be a multiple of 3. Since 176 is not divisible by 3, you will not be able to find three consecutive integers with that total.

If you call the first of the two "n", the second must be "n+2", so you need to solve:n + (n + 2) = 176 Or you can do some trial and error.

104 and 72

41.8923.8% of 176= 23.8% * 176= 0.238 * 176= 41.89

Related questions

87 and 89

87 and 89.

87 and 89.

The numbers are 87 and 89.The integers are 87 and 89.

There are three consecutive integers. Let's call the middle one x. The one before it is x - 1 and the one after it is x + 1. Adding them together equals 3x. That means that whatever they equal has to be a multiple of 3. Since 176 is not divisible by 3, you will not be able to find three consecutive integers with that total.

First of all, the sum of 3 odd numbers always equals an odd number and 176 is even so this is NOT possible.If you did not know this you could let n be the first odd number, n+2 is the next and n+4 is the third.Add them up and we have n+n+2+n+4=176 or3n+6=176 so3n=170Now you see that 170 is NOT divisible by 3 so ONCE again you see that there is NO solution to this problem. That is to say, there are NOT 3 odd consecutive integers whose sum is 176.

There are no three consecutive even integers that add up to 176.Let the three consecutive even integers be (2n-2), 2n & (2n+2). Then their sum is:(2n-2) + 2n + (2n+2) = 6n⇒ the total must be a multiple of 6.To be a multiple of 6 the number must be an even multiple of 3; for 176:It is even;1 + 7 + 6 = 14; 1 + 4 = 5 which has a remainder of 2 when divided by 3, so 176 is not a multiple of 3.Thus 176 is not a multiple of 6 and so cannot be the sum of three consecutive even integers.

The numbers are 87 and 89.

If you call the first of the two "n", the second must be "n+2", so you need to solve:n + (n + 2) = 176 Or you can do some trial and error.

First, an equation is needed. We will designate the first integer as N, and the second as N + 2. The sum of the two numbers is 176, so the equation should look like this:N + N + 2 = 176Now it needs to be added:2N + 2 = 176Now both sides need to be subtracted by 2:2N = 174Now both sides need to be divided by 2:N = 87Therefore, the first integer is 87. Since the second integer is designated by N + 2, and N is equal to 87, the second integer is 87 plus 2, which is equal to 89.So the two consecutive odd integers whose sum is 176, are 87 and 89.

They are: 175+176+177 = 528

The greatest common multiple of any set of integers is infinite.