Numbers that are divisible by 80 are itself and any of its other multiples
101
1, 2, 4, 5, 8, 10, 16, 20, 40, 80
If the last 4 digits are divisible by 80, the entire number is divisible by 80.But really, it is hardly worth-while to learn divisibility rules for a large amount of numbers; only for a few small numbers. Normally it is easier to just do the division.
Three of them.
Numbers that are divisible by 80 are itself and any of its other multiples
Yes and by any of its factors
No; it is divisible only by its factors (1, 2, 4, 5, 8, 10, 16, 20, 40, and 80).
101
There are 80 such numbers.
40, 80, 120... Any multiple of 40.
Oh, dude, numbers that are divisible by both 4 and 5 are multiples of their least common multiple, which is 20. So, like, 20, 40, 60, and so on are all numbers that fit the bill. But hey, who's counting, right?
1, 2, 4, 5, 8, 10, 16, 20, 40, 80
80%. Out of every ten numbers, one is divisible by 10, and that same one plus one moreare both divisible by 5. The remaining eight are divisible by neither 5 nor 10.
If the last 4 digits are divisible by 80, the entire number is divisible by 80.But really, it is hardly worth-while to learn divisibility rules for a large amount of numbers; only for a few small numbers. Normally it is easier to just do the division.
Both numbers are divisible by 5.
Three of them.