(a + b)² = a² + b². If you expand the left side, you have a² + 2ab + b² = a² + b².
Subtracting a² and b² from both sides, you have: 2ab = 0. So if either a=0 or b=0 the equation is satisfied.
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No because no 2 numbers can be squared to equal 4. 1 squared is 1 2 squared is 4 so the lowest answer is 5.
Without an equality sign the expression given can't be considered to be an equation and therefore has no solution.
10 squared is 100 12 squared is 144 100+144= 244 10+12= 22
x/1 + x/x = 84 where x = a prime number that is divisible by 1 and itself. Then find common denominator of 1x. Then we have x squared/1x + x/1x = 84. To simplify this will be x squared + x/1x = 84. The this becomes 1 + x = 84. Then x = 83. The prime numbers are 1 and 83 which fit the equation.
4 squared is 16, so any numbers that are 16 apart. For example 46-30=16