It is a rhombus whose diagonals are perpendicular and meeting each other at right angles.
It makes sense because it is true. There are other quadrilaterals whose diagonals are perpendicular.
How about a rhombus or a kite
It is an 8 sided octagon whose 8 interior angle add up to 1080 degrees and has 20 diagonals
A square, rhombus and a kite are examples of shapes whose diagonals bisect each other at 90 degrees
A square or a rectangle.
I think this is impossible the diagonals of a four sided figure will cross
It is a rhombus whose diagonals are perpendicular and meeting each other at right angles.
It is a kite or a rhombus both of which have unequal diagonals that are perpendicular to each other creating right angles.
It makes sense because it is true. There are other quadrilaterals whose diagonals are perpendicular.
How about a rhombus or a kite
It is an 8 sided octagon whose 8 interior angle add up to 1080 degrees and has 20 diagonals
A rectangle or a parallelogram
A square, rhombus and a kite are examples of shapes whose diagonals bisect each other at 90 degrees
494.5
No, absolutely not. Not only are they intersecting, they are perpendicular. Perpendicular means that they are at right angles to each other (90 degrees). In fact, any rhombus has perpendicular diagonals. A rhombus is any quadrilateral whose 4 sides are equal.
It is a kite whose diagonals are perpendicular to each other and form 4 right angles.