Q: Fraction for 4x2 plus 10x plus 6?

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4x2+3x+6+5x+3x+6 = 4x2+11x+12 when simplified

2x + 10x - 6 = 12x - 6

x + 13x + 10x = 50 - 6

-4x2 + 11x - 6 factors to: (-4x + 3) (x - 2)

x3 + 4x2 + 6x + 24 = (x2 + 6)(x + 4)

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The operators are missing, the possible factorisations are:4x2 + 10x + 6 = 2(2x + 3)(x + 1)4x2 - 10x + 6 = 2(2x - 3)(x - 1)4x2 + 10x - 6 = 2(2x - 1)(x + 3)4x2 - 10x - 6 = 2(2x + 1)(x - 3)

4x2+3x+6+5x+3x+6 = 4x2+11x+12 when simplified

-10x -9

2x + 10x - 6 = 12x - 6

x + 13x + 10x = 50 - 6

-4x2 + 11x - 6 factors to: (-4x + 3) (x - 2)

x3 + 4x2 + 6x + 24 = (x2 + 6)(x + 4)

6 + 10x + 3 = 9 + 10x

Assuming the missing signs are pluses, that factors to 2(x + 1)(2x + 3)

6-x+12 = 10x+7 6+12-7 = 10x+x 11 = 11x x = 1

6 + (4 x 2)= 6 + 8= 14

10