For example, by calculating the surface of a circle, using an integral.
ripple factor:=21/2 /3 *Xc/XL
Where pi (~ 3.1416) is represented by π, The formula C= πr2 yields the formula r2 = (C/π) therefore r = square root (C/π). ...which is the same as : r = (C/π)1/2.
I derive that this question needs to be moved.
The way I remember the equation for the volume of a cylinder is by thinking of it as a circle with height. The area of a circle is pi x r^2, so the volume of a cylinder is pi x r^2 x h. We need to derive r from the circumference. Since pi is the ratio of any circle's circumference to its diameter, just divide the circumference by pi to get the diameter, then divide that by 2 to get the radius. So the radius is (2.25/pi) ft. When we square that, we have (5.0625/pi^2) ft^2. Multiplying that by pi gives us (5.0625/pi) ft^2. Multiplying by the height makes it (65.8125/pi) ft^3, which is roughly 21 cubic feet.HAPPY PI DAY on 3/14! Better yet, HAPPY PI MINUTE at 3/14/15 9:27!
circumference/diameter
the value of pi can be derived as the ratio between the circumference and diameter of every circle, say pi = circumference/diameter
For example, by calculating the surface of a circle, using an integral.
ripple factor:=21/2 /3 *Xc/XL
The area of the base of a cylinder = Pi times Radius squared. Diameter of a cylinder = 2 times Pi times Radius. To find the diameter derive the area of the base by Pi and then square root the answer. That will give you the value of the radius. Multiply that answer by 2 times Pi and you will have your answer.
Measure its radius in feet or derive it from the diameter or circumference. A circle with radius r feet has an area of pi*r^2 square feet.
Where pi (~ 3.1416) is represented by π, The formula C= πr2 yields the formula r2 = (C/π) therefore r = square root (C/π). ...which is the same as : r = (C/π)1/2.
Derive the castiglino's theorem
it derive from Negro...lol
To derive the cross sectional area of a two liter bottle do the following formula. Area = (radius * 2.54 cm/in)^2 * pi = X cm^2.
I derive that this question needs to be moved.
Answer should be; Δgz = 2*pi*G*rho(z2-z1 + sqrt(a^2+z1^2)-sqrt(a^2+z2^2)), Where a is the radius of the cylinder at depth z.