Given the initial velocity V, and the angle from the ground A, the total distance travelled X will be: X = 2 V2 cos(A) sin(A) / g
where "g" is the acceleration due to gravity, on earth g is approximately 9.81 m/s2.
You will notice that the mass of the object does not affect the distance traveled. We can derive this by first determining how long the projectile will be in the air. If the initial velocity is V, then the initial vertical velocity is Vsin(A). The vertical velocity will decrease at a rate of 'g' until the vertical velocity reaches zero (known as apogee), and the projectile starts falling down. The time from launch to apogee will be Vsin(A)/g.
The time for the projectile to go up is the same as for the projectile to fall down again, so the total time in the airis 2Vsin(A)/g.
Assuming we neglect friction, the horizontal velocity is Vcos(A) and does not change. The total distance traveled horizontally is the horizontal speed multiplied by the time spend in the air. So X = 2Vsin(A)/g * Vcos(A) = 2V2cos(A)sin(A)/g.
The maximum distance is achived with an angle of 45o. The distance travelled is symmetric around this value, i.e. an angle of 50o will give the same distance as 40o, and an angle of 15owill give the same distance as 75o.
No, you cannot.
no, you need to know its initial velocity to determine this; if initial velocity is zero then distance is 1/2 acceleration x time squared
Speed describes the distance traveled by an object divided by the time in which the distance was traveled, if the direction is not specified.
distance traveled = speed multiplied by time taken.
The distance it travels and how long it took to travel that far. To calculate speed you do (total distance traveled)/(total time taken)
To determine how far a projectile travels horizontally, you need to know the initial velocity of the projectile, the angle at which it was launched, and the acceleration due to gravity. Using these values, you can calculate the horizontal distance traveled using the projectile motion equations.
To determine the initial velocity in projectile motion, you can use the equation v (x y) / t, where v is the initial velocity, x is the horizontal distance traveled, y is the vertical distance traveled, and t is the time taken.
To determine how far a projectile travels horizontally, you need to know the initial velocity of the projectile, the angle at which it was launched, and the acceleration due to gravity. Using these values, you can calculate the time of flight and then multiply it by the horizontal component of the initial velocity to find the horizontal distance traveled.
To determine the launch velocity of a projectile, you can use the projectile motion equations. By measuring the initial height, horizontal distance traveled, and the angle of launch, you can calculate the launch velocity using trigonometry and kinematic equations.
The horizontal distance traveled by a projectile is determined by the initial velocity of the projectile, the angle at which it was launched, and the time of flight. It can be calculated using the equation: horizontal distance = (initial velocity * time * cosine of launch angle).
90
The weapon should be fired at a 45-degree angle from the horizontal to achieve the minimum distance traveled by the projectile. This angle maximizes the range (horizontal distance) of the projectile by balancing the vertical and horizontal components of its velocity. At any other angle, the total distance traveled would be greater.
measure
The formula for the horizontal distance traveled by a horizontally launched projectile is: range = initial velocity * time. This formula assumes that there is no air resistance and that the projectile is launched horizontally.
No, you cannot.
it depends on the gravitational force of attraction of earth and air resistance. if we are neglecting air resistance, the max.horizontal distance is according to this formulae, V0/2 * sin (2theta) where V0 is the initial velocity theta is the angle with x axis and the projection.
The optimal angle to fire a projectile if the objective is distance is 45 degrees. It follows that the distance traveled decreases whether the angle is increased or decreased from 45.