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Go 18.5 units of distance in any direction. Turn 90 degrees clockwise and go 18.5 units of distance in a straight line. Turn 90 degrees clockwise and go 18.5 units of distance in a straight line. Turn 90 degrees clockwise and go 18.5 units of distance in a straight line.You will have travelled along a square route whose total distance is 74 units. Alternatively you could have turned counter clockwise each time.
Go 8 units of distance in any direction. Turn 90 degrees clockwise and go 8 units of distance in a straight line. Turn 90 degrees clockwise and go 8 units of distance in a straight line. Turn 90 degrees clockwise and go 8 units of distance in a straight line.You will have travelled along a square route whose total distance is 32 units. Alternatively you could have turned counter clockwise each time.
Go 0.75 units of distance in any direction. Turn 90 degrees clockwise and go 0.75 units of distance in a straight line. Turn 90 degrees clockwise and go 0.75 units of distance in a straight line. Turn 90 degrees clockwise and go 0.75 units of distance in a straight line.You will have travelled along a square route whose total distance is 3 units. Alternatively you could have turned counter clockwise each time.
It depends on the route that you take. There is nothing in the question to suggest that the distance of interest is the shortest distance. In real life, the quickest route is not necessarily the shortest since travelling on highways may be faster even if longer. In such cases the relevant distance may not be the shortest. Also, you might wish to take the "scenic" route. In any built-up area the shortest meaningful distance between two points will not be "as the crow flies": the taxicab metric (for example 3 blocks East and 4 blocks North), which was developed by Minkowsky, is more appropriate. On the surface of a sphere, such as the Earth, the shortest distance is an arc of the great circle. In most cases this is not the straight line on a map.
i need a code the first code must complete a circle and form a minimum distance route for a TSP. the second code should improve the result of the first code by simulated annealing with 2 opt. Again thank you for the help.