3+h/6 7-3(h/6) 4(h/6) 4*6=24 24/6=4 4+3=7 Therefore the variable h equals 24
1:16:43+3:27:14= 4 hours 43 minutes 57 seconds. Was this helpful?
There are 12 possible outcomes: ....................................................... ............................./---- 1 = H + 1 ..... ............................/.......................... .........................../../--- 2 = H + 2 ..... ........................../../......................... ........................./../../-- 3 = H + 3 ..... .............../-- H _/_/_/......................... ............../.........\..\..\-- 4 = H + 4 ...... ............./...........\..\.......................... ............/.............\..\--- 5 = H + 5 ...... .........../...............\........................... ........../.................\---- 6 = H + 6 ...... ........./............................................. .........\............................................. ..........\................./---- 1 = T + 1 ...... ...........\.............../........................... ............\............./../--- 2 = T + 2 ...... .............\.........../../.......................... ..............\........./../../-- 3 = T + 3 ...... ...............\-- T _/_/_/......................... ........................\..\..\-- 4 = T + 4 ...... .........................\..\.......................... ..........................\..\--- 5 = T + 5 ...... ...........................\........................... ............................\---- 6 = T + 6 ...... .......................................................
Suppose the number of Heads is H where H = 0, 1, 2, 3 ,4. Then the number of Tails is 4-H. Their product is X = H*(4-H) = 0, 3, 4, 3, 0 Thus X is NOT more than 1 only if H = 0 or H = 4 The probability of each of these events is 2-4 and so their combined probability is 2-3 = 1/8. Therefore, Prob(X > 1 ) = 1 / 1/8 = 7/8
3 + h = 3 + 100.25 = 103.25
3+h/6 7-3(h/6) 4(h/6) 4*6=24 24/6=4 4+3=7 Therefore the variable h equals 24
I h ave no idea I h ave no idea
There are 16 possible outcomes, each of which is equally likely. So each has a probability of 1/16 HHHH: X = H*T = 4*0 = 0 HHHT: X = H*T = 3*1 = 3 HHTH: X = H*T = 3*1 = 3 HTHH: X = H*T = 3*1 = 3 THHH: X = H*T = 3*1 = 3 HHTT: X = H*T = 2*2 = 4 HTHT: X = H*T = 2*2 = 4 HTTH: X = H*T = 2*2 = 4 THHT: X = H*T = 2*2 = 4 THTH: X = H*T = 2*2 = 4 TTHH: X = H*T = 2*2 = 4 HTTT: X = H*T = 1*3 = 3 THTT: X = H*T = 1*3 = 3 TTHT: X = H*T = 1*3 = 3 TTTH: X = H*T = 1*3 = 3 TTTT: X = H*T = 0*4 = 0 So, the probability distribution function of X is f(X = 0) = 1/16 f(X = 1) = 4/16 = 1/4 f(X = 2) = 6/16 = 3/8 f(X = 3) = 4/16 = 1/4 f(X = 4 = 1/16 and f(X = x) = 0 for all other x
1:16:43+3:27:14= 4 hours 43 minutes 57 seconds. Was this helpful?
1-h
The formula for H plus 1 plus H minus 1 is 2H. This is because the +1 and -1 charges cancel each other out, leaving only the H atom.
It's a simple linear equation in 'h' .Its solution is [ h = 4 ].
There are 12 possible outcomes: ....................................................... ............................./---- 1 = H + 1 ..... ............................/.......................... .........................../../--- 2 = H + 2 ..... ........................../../......................... ........................./../../-- 3 = H + 3 ..... .............../-- H _/_/_/......................... ............../.........\..\..\-- 4 = H + 4 ...... ............./...........\..\.......................... ............/.............\..\--- 5 = H + 5 ...... .........../...............\........................... ........../.................\---- 6 = H + 6 ...... ........./............................................. .........\............................................. ..........\................./---- 1 = T + 1 ...... ...........\.............../........................... ............\............./../--- 2 = T + 2 ...... .............\.........../../.......................... ..............\........./../../-- 3 = T + 3 ...... ...............\-- T _/_/_/......................... ........................\..\..\-- 4 = T + 4 ...... .........................\..\.......................... ..........................\..\--- 5 = T + 5 ...... ...........................\........................... ............................\---- 6 = T + 6 ...... .......................................................
Hydrogen on apex chris
H-4 engine: 1 - 3 - 2 - 4; H-6 engine: 1 - 6 - 3 - 2 - 5 - 4
1/4 * 3/3 = 3/12 5/12 3/12 + 5/12 = (I think you can solve it yourself from here)
Suppose the number of Heads is H where H = 0, 1, 2, 3 ,4. Then the number of Tails is 4-H. Their product is X = H*(4-H) = 0, 3, 4, 3, 0 Thus X is NOT more than 1 only if H = 0 or H = 4 The probability of each of these events is 2-4 and so their combined probability is 2-3 = 1/8. Therefore, Prob(X > 1 ) = 1 / 1/8 = 7/8