Neither, some multiples of 8 are: 8,16,24,32,40,48,56,64
Since 8 is a multiple of 2 and 4, all multiples of 8 are also multiples of both of them. Thus, Jose and maria are both correct.
Multiples of 6 end in 6, 2, 8, 4 or 0.
The integer factors of 8 are 1, 2, 4, -1, -2, -4, -8 and 8. There are infinitely many multiples, but to name a few, 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, and 104 are all multiples of 8.
Multiply each of these numbers by different integers, to get their multiples. For example, the multiples of 4 are:4 x 0 = 0 4 x 1 = 4 4 x 2 = 8 etc.
1 2 4 8 ( 1*8 2*4 4*2 8*1) Find anything that you can multiply by a number and get 8.
If ordered by size, only every other multiple of 2 is a multiple of 4. All multiples of 4 are multiples of 2.
Neither, some multiples of 8 are: 8,16,24,32,40,48,56,64
Since 8 is a multiple of 2 and 4, all multiples of 8 are also multiples of both of them. Thus, Jose and maria are both correct.
No, they are factors.
LCM: 8
8 and 16
All multiples of 4; 4, 8, 12 and so on.
Multiples for 8 are - 1 and 8, 2 and 4.
They are 4, 8 and 16.
4, 8 and 12 are the first 3 common multiples of 2 and 4
No, they are just multiples of 2.