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If x is between a and c how are ax and ac related?
If a,b, and c are positive a < x < b means ax < cx If a,b , and c are negative a < x < b means ax > cx
What is ax times ax?
(ax)(ax) = a2 + 2ax + x2
Program to subtract two 8 bit numbers using 8086 microprocessor?
I have a code for 16 bit subtraction.. just replace ax by al,bx by bl etc... .code main proc mov ax,@data mov ds,ax lea dx,msg ;printing msg mov ah,09h int 21h mov ax,x ;ax=x(any number) mov bx,y ;bx=y( " ") cmp ax,0 ;jump to l3 if ax is negtive jb l3 cmp bx,0 ;jump to l6 if bx is negative jb l6 cmp ax,bx ;if ax<bx,then jump to l1 jl l1 sub ax,bx ;else normal sub mov diff,ax ;diff=result is stored jmp l2 l1: ;iff (+)ax<(+)bx neg bx ;bx=-bx clc add ax,bx neg ax ;-ans=ans mov diff,ax mov dx,2dh ;print '-' mov ah,02h int 21h jmp l2 l3: ;iff (-)ax neg ax ;-ax=ax cmp bx,0 ;jump to l4 if bx is negative jb l4 clc add ax,bx ;ax=(+)ax+(+)bx mov ax,diff mov dx,2dh ;print '-' mov ah,02h int 21h jmp l2 l4: ;if (-)ax & (-)bx neg bx ;-bx=bx cmp ax,bx ;if ax>bx then jump to l5 jg l5 sub ax,bx ;else ax-bx mov diff,ax mov dx,2dh ;print '-' mov ah,02h int 21h jmp l3 l5: ;if(-)ax>(-)bx xchg ax,bx ;exchange ax and bx sub ax,bx ;ax-bx mov diff,ax ;ans is positive jmp l2 l6: ;iff (-)bx neg bx ;-bx=bx add ax,bx ;ax-(-)bx mov diff,ax ;ans will be positive mov ah,4ch int 21h main endp
What is the compound sentence of abs value ax plus b equals 15?
ax + b = 15 or ax + b = -15
Why is 2 to the power 0 is 1?
Any number, raised to the power 0 is 1.This comes from the index law: ax* ay= ax+yLet y = 0 and you have ax* a0= ax+0But x+0 = x so the right hand side is ax.That means ax* a0= axSince this is true for all a, a0must be the multiplicative identity = 1.Any number, raised to the power 0 is 1.This comes from the index law: ax* ay= ax+yLet y = 0 and you have ax* a0= ax+0But x+0 = x so the right hand side is ax.That means ax* a0= axSince this is true for all a, a0must be the multiplicative identity = 1.Any number, raised to the power 0 is 1.This comes from the index law: ax* ay= ax+yLet y = 0 and you have ax* a0= ax+0But x+0 = x so the right hand side is ax.That means ax* a0= axSince this is true for all a, a0must be the multiplicative identity = 1.Any number, raised to the power 0 is 1.This comes from the index law: ax* ay= ax+yLet y = 0 and you have ax* a0= ax+0But x+0 = x so the right hand side is ax.That means ax* a0= axSince this is true for all a, a0must be the multiplicative identity = 1.
If x is between a and c how are ax and ac related?
If a,b, and c are positive a < x < b means ax < cx If a,b , and c are negative a < x < b means ax > cx
What is ax times ax?
(ax)(ax) = a2 + 2ax + x2
What does the prefix ax mean?
The prefix "ax" typically means "to cut" or "to split." It is often used in words related to chopping or dividing, such as "axiom" (a self-evident truth) or "axiology" (the study of values).
How is a Michigan ax different from other styles of ax?
The difference is in the shape of the head of the ax.
What does the latin root 'ax' mean?
The Latin root 'ax' means "to go, to move, to lead." It is derived from the Latin word "agere," which means "to do or drive." This root is commonly found in words related to action, movement, and leadership.
What is the homonym of ax?
The homonym of "ax" is "acts." "Ax" is a tool used for chopping, while "acts" refers to actions or performances.
What is the Tagalog of ax?
Tagalog Translation of AX: palakol
Why is that needle floats in water?
Surface Tension ~ see related link below .
Where is the battle ax from?
From the basic woodsmans ax.
What simple machine is ax?
The ax is a wedge.
What is better the esp ltd ax-414 or the ax-404?
The ESP LTD AX-414.
Write a program to subtract two 16 bit numbers in microprocessor 8086?
.code main proc mov ax,@data mov ds,ax lea dx,msg ;printing msg mov ah,09h int 21h mov ax,x ;ax=x mov bx,y ;bx=y cmp ax,0 ;jump to l3 if ax is negtive jb l3 cmp bx,0 ;jump to l6 if bx is negative jb l6 cmp ax,bx ;if ax<bx,then jump to l1 jl l1 sub ax,bx ;else normal sub mov diff,ax ;diff=result is stored jmp l2 l1: ;iff (+)ax<(+)bx neg bx ;bx=-bx clc add ax,bx neg ax ;-ans=ans mov diff,ax mov dx,2dh ;print '-' mov ah,02h int 21h jmp l2 l3: ;iff (-)ax neg ax ;-ax=ax cmp bx,0 ;jump to l4 if bx is negative jb l4 clc add ax,bx ;ax=(+)ax+(+)bx mov ax,diff mov dx,2dh ;print '-' mov ah,02h int 21h jmp l2 l4: ;if (-)ax & (-)bx neg bx ;-bx=bx cmp ax,bx ;if ax>bx then jump to l5 jg l5 sub ax,bx ;else ax-bx mov diff,ax mov dx,2dh ;print '-' mov ah,02h int 21h jmp l3 l5: ;if(-)ax>(-)bx xchg ax,bx ;exchange ax and bx sub ax,bx ;ax-bx mov diff,ax ;ans is positive jmp l2 l6: ;iff (-)bx neg bx ;-bx=bx add ax,bx ;ax-(-)bx mov diff,ax ;ans will be positive mov ah,4ch int 21h main endp
