It is 47.25 cubic centimetres.
Let the sides be x and x-7 So using Pythagoras: x2+(x-7)2 = 172 => 2x2-14x-240 = 0 Solving the quadratic equation gives x a positive value of 15 Therefore sides are: 15 and 15-7 = 8 Perimeter: 17+15+8 = 40 cm
width = (x + 4) cm length = [(x + 4) + (x + 7)] cm Rectangle Perimeter = 2[(x + 4) + (x + 4 + x + 7)] cm Rectangle Perimeter = 2[(x + x + x) + (4 + 4 + 7)] cm Rectangle Perimeter = 2(3x + 15) cm Rectangle Perimeter = (6x + 30) cm
15 x 35 mm = 525 mm, which is also equal to 52.5 cm.
The product of 15, 2.8, and 0.8 is equal to 33.6 cm³.
It is 47.25 cubic centimetres.
NO ! You cubed the 'cm' part OK. Why did you not also cube the '15' part ? Look at this: You have a cube, 15 cm on each side. What is its volume ? Length = 15 cm Width = 15 cm Height = 15 cm Volume = (Length) x (width) x (height) (15 cm) x (15 cm) x (15 cm) = 3,375 cm3 An even slightly better way to look at it: (15 cm)3 = (15)3 x (cm)3 = (3,375) (cm3)
Suppose the shorter side is x cm.Then the longer side is x + 3.5 cm. Therefore the perimeter is 2*(x + x + 3.5) = 4x + 7 cm. Now 4x + 7 = 67 so that 4x = 60 and x = 15 and then x + 3.5 = 18.5 Therefore the sides of the rectangles are 15 cm and 18.5 cm.
If that is the side length, just multiply 15 cm x 15 cm x 15 cm.
Let the sides be x and x-7 So using Pythagoras: x2+(x-7)2 = 172 => 2x2-14x-240 = 0 Solving the quadratic equation gives x a positive value of 15 Therefore sides are: 15 and 15-7 = 8 Perimeter: 17+15+8 = 40 cm
width = (x + 4) cm length = [(x + 4) + (x + 7)] cm Rectangle Perimeter = 2[(x + 4) + (x + 4 + x + 7)] cm Rectangle Perimeter = 2[(x + x + x) + (4 + 4 + 7)] cm Rectangle Perimeter = 2(3x + 15) cm Rectangle Perimeter = (6x + 30) cm
15 x 35 mm = 525 mm, which is also equal to 52.5 cm.
how big is 30 cm x 40cm
The product of 15, 2.8, and 0.8 is equal to 33.6 cm³.
1800cm3
7 cm * 4 cm * 3 cm = 7 * 4 * 3 * cm * cm * cm = 84 cm3
20 cm x 15 cm = 300 cm2