There are 10 small cubes along the length, along the width and along the height of the big cube. There is, therefore, 10*10*10 = 1000 cubes.There are 10 small cubes along the length, along the width and along the height of the big cube. There is, therefore, 10*10*10 = 1000 cubes.There are 10 small cubes along the length, along the width and along the height of the big cube. There is, therefore, 10*10*10 = 1000 cubes.There are 10 small cubes along the length, along the width and along the height of the big cube. There is, therefore, 10*10*10 = 1000 cubes.
Area = Length * width A = 12 * 10 A = 120 units 2
Area = Length * Width = 10*3 = 30 square units.
The length is 20 units and the width is 10 units
width:10,length;17 17*2+10*2=54
There are 10 small cubes along the length, along the width and along the height of the big cube. There is, therefore, 10*10*10 = 1000 cubes.There are 10 small cubes along the length, along the width and along the height of the big cube. There is, therefore, 10*10*10 = 1000 cubes.There are 10 small cubes along the length, along the width and along the height of the big cube. There is, therefore, 10*10*10 = 1000 cubes.There are 10 small cubes along the length, along the width and along the height of the big cube. There is, therefore, 10*10*10 = 1000 cubes.
What do we know about the perimeter of a rectangle? perimeter = 2 × (length + width) → 2 × (length + width) = 20 in → length + width = 10 in → length = 10 in - width What do we know about the area of a rectangle: area = length × width → length × width = 24.4524 in² But from the perimeter we know the length in terms of the width and can substitute it in: → (10 in - width) × width = 24.4524 in² → 10 in × width - width² = 24.4524 in² → width² - 10 in × width + 24.4524 in² = 0 This is a quadratic which can be solved by using the formula: ax² + bx + c → x = (-b ±√(b² - 4ac)) / (2a) → width = (-10 ±√(10² - 4 × 1 × 24.4524)) / (2 × 1) in → width = -5 ± ½√(100 - 97.8096) in → width = -5 ±½√2.1904 in → width = -5 ± 0.74 in → width = 4.26 in or 5.74 in → length = 10 in - 4.26 in = 5.74 in or 10 in - 5.74 in = 4.26 in (respectively) By convention the width is the shorter length (though it doesn't have to be) making the width 4.26 in and the length 5.74 in. Thus the rectangle is 5.74 in by 4.26 in
Area = Length * width A = 12 * 10 A = 120 units 2
Area = Length * Width = 10*3 = 30 square units.
The length is 20 units and the width is 10 units
10 width
width:10,length;17 17*2+10*2=54
length is 30 width is 10
Length is usually 10 metres and Width is usually 8.
Length Plus width = half of perimeter = 176. Width is one-eleventh of this and length is ten-elevenths ie 16 and 160 respectively.
width 1, length 10 width 2, length 5
A square is two-demensional. Therefore, it has only width and length. However, a cube is three-demensional - length, width and height.If you have a cube and you know it length and height, you can calculate its width as follows.The volume of a cube is equal to the width x length x the height. Therefore, width equals volume divided by length x height.If a cube has a volume of 1000 and the length of the cube is 10 and the height is 10, then:1000 = L (length) x 10 x 10L = 1000 divided by 100, which equals 10