the area o rectangle is 6 x 12 = 72 and the area of trapezoid is 1/2 (12+16) X 7 = 98. The sum is 72 + 98 = 170 Square cm
1 cm X 12 cm or 12 cm X 1 cm = 12 square cm 2 cm X 6 cm or 6 cm X 2 cm = 12 square cm 3 cm X 4 cm or 4 cm X 3 cm = 12 square cm These are the only WHOLE numbers that are rectangles, and there are 6 of them.
16 and 12
A rectangle with sides of length x cm and 16/x cm will have an area of 16 sq cm for any value x that is greater than 0.
16 cm x 3 sides = 16 x 3 = 48 cm
16000mm cubed or 16 cm cubed
8 x 24? 16 x 12? 6 x 32? etc etc
the area o rectangle is 6 x 12 = 72 and the area of trapezoid is 1/2 (12+16) X 7 = 98. The sum is 72 + 98 = 170 Square cm
1 cm X 12 cm or 12 cm X 1 cm = 12 square cm 2 cm X 6 cm or 6 cm X 2 cm = 12 square cm 3 cm X 4 cm or 4 cm X 3 cm = 12 square cm These are the only WHOLE numbers that are rectangles, and there are 6 of them.
16 and 12
16 sq cm. Suppose the original square had sides of x cm. Then the folded rectangle has pairs of sides of length x and x/2 cm. The perimeter is 2(x + x/2) = 3x. So 3x = 12 so that x = 4 and the area of the original square, with sides of 4 cm is 16 sq cm.
A rectangle with sides of length x cm and 16/x cm will have an area of 16 sq cm for any value x that is greater than 0.
16 cm x 3 sides = 16 x 3 = 48 cm perimeter.
16 cm x 3 sides = 16 x 3 = 48 cm
1 ft = 30.48 cm (exactly) ⇒ 8 ft x 16 ft = (8 x 30.48) cm x (16 x 30.48) cm = 243.84 cm x 487.68 cm
how big is 30 cm x 40cm
Let the base be (x-x/4) and the height be x:- 1/2*(x-x/4)*x = 96 sq cm Multiply both sides by 2 and multiply out the brackets: x2-x2/4 = 192 Multiply all terms by 4: 4x2-x2 = 768 => 3x2 = 768 Divide both sides by 3 and then square root both sides: x = 16 cm So: height = 16 and base = 12 Using Pythagoras' theorem: hypotenuse = 20 Dimensions: hypotenuse = 20 cm, height = 16 cm and base = 12 cm Perimeter: 20+16+12 = 48 cm