Diameter: 157/3.14 = 50 meters
Radius: square root of (50/pi) = 3.989422804 Diameter: 2*3.989422804 = 7.978845608 or as 8 meters to nearest integer
There are: pi*25^2 = 625*pi square meters
The circumference of a circle with a diameter of 13.4 meters is: 42.1 meters (diameter x Pi = circumference).
This is a simple algebra problem. The Sun has a diameter of 1,390,000 km, and the Earth has a diameter of 12,756 km. If I'm making a model of the Sun that is 1.26 meters in diameter, what should the diameter of the model Earth be? So, 12756/1390000*1.226 = 0.0112509755 meters, or 1.125 cm. So, if the sun-model is 1.26 meters, about the size of a bicycle wheel, then the earth-model is about the size of a pea.
A 50-meter diameter is equivalent to the distance across a circle from one edge to the other passing through the center, measuring 50 meters in length. In terms of area, a circle with a 50-meter diameter would have a radius of 25 meters and an area of approximately 1,963.5 square meters (πr^2). This size can be visualized as a circle with a radius of 25 meters or a little over 82 feet.
Diameter: 157/3.14 = 50 meters
The Earth has a diameter of about 12,742 kilometers, which is equivalent to 12.742 million meters.
Radius: square root of (50/pi) = 3.989422804 Diameter: 2*3.989422804 = 7.978845608 or as 8 meters to nearest integer
It's one half inch (.50) in diameter.
Varies from 50 to 120 microns. On average a human hair is usually around 100 microns.
There are: pi*25^2 = 625*pi square meters
Oh, dude, this is like basic math 101. The diameter of a circle is just twice the radius, so if the radius is 1 meter, the diameter is 2 meters. It's like the circle's way of saying, "I'm just twice as big as my radius, no big deal."
As an asteroid - 2010 TK7 is a lightweight, with a diameter of about 300 meters (1,000 ft)
Area = pi*50 squared = 7853.982 square meters rounded to 3 decimal places
The circumference of a circle with a diameter of 13.4 meters is: 42.1 meters (diameter x Pi = circumference).
This is a simple algebra problem. The Sun has a diameter of 1,390,000 km, and the Earth has a diameter of 12,756 km. If I'm making a model of the Sun that is 1.26 meters in diameter, what should the diameter of the model Earth be? So, 12756/1390000*1.226 = 0.0112509755 meters, or 1.125 cm. So, if the sun-model is 1.26 meters, about the size of a bicycle wheel, then the earth-model is about the size of a pea.