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if y=7/(x^3)-4/x
then
by the quotient rule
y'=(((0)(x^3)-(7(3x^2))/((x^3)^2))-(((0x)-(4))/(x^2))

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Q: How can I find the derivative of y equals 7 divided by x to the 3rd power subtracted by 4 divided by x?
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