How about 4 times 7 is 28 and 8 divded by 2 is 4
Four of them: 4 times 7 = 28
99 divided by 0.99
In canasta, a meld of sevens can be made using wild cards, such as jokers or twos. However, when forming a canasta, at least one natural seven (without wild cards) must be included in the meld. Additionally, the meld must consist of a minimum of four cards to be considered a valid canasta. Therefore, while you can include wild cards, you can't create a canasta of sevens entirely out of wild cards.
As a solution to the four fours problem (using the number four no more than four times to come up with the solution, 31 is equal to (4!+4)/4+4!
Google "Four Fours" and you will find a number of solutions, presented more comprehensively than we can.
((7+7)*7) - 7
Four of them: 4 times 7 = 28
Well, isn't that a happy little problem to solve! To make 100 using four sevens, you can try this: 77 + 7/7 = 100. Just like painting a beautiful landscape, sometimes it's about mixing and blending things together in a creative way to achieve your desired result.
You could go (7+7+7)7=147
99 divided by 0.99
eleven to the power of eleven
5*4+3+2
In canasta, a meld of sevens can be made using wild cards, such as jokers or twos. However, when forming a canasta, at least one natural seven (without wild cards) must be included in the meld. Additionally, the meld must consist of a minimum of four cards to be considered a valid canasta. Therefore, while you can include wild cards, you can't create a canasta of sevens entirely out of wild cards.
As a solution to the four fours problem (using the number four no more than four times to come up with the solution, 31 is equal to (4!+4)/4+4!
(8x8)=64
You divide 7 by 4 which is 1.75.
4! - 4 + 4/4