('X' rev/minute) x (2 pi radian/rev) x (1 minute/60 sec) = 2 pi X/60 = 0.10472 Xrad/sec (rounded)
For starter, 1 rad/S = 0.159 rev/S
(550 - 200) rev per minute = -350 rev per minute / 60 sec per minute = (-35/6 rev per second) change in angular velocityAngular acceleration = (change in angular velocity) / (time for the change) =(-35/6 rev per second) x (2 pi radians per rev) / 4.5 seconds = -8.1449 radians per second2("Meters per sec sq" can't be a unit of angularacceleration, since angles can't be measured in meters.)
There are 60 sec in one min 35 rev/min x 45/60 = 26.25 revs
60 mph = 88 feet/sec = (88 x 12) inches per sec = (88 x 12 x 60) in/min = 63,360 inches per minuteCircumference of the wheel = 2 pi R = 30 pi inches.RPM = (63,360) / (30 pi) = 672.27 rev per min (rounded)
('X' rev/minute) x (2 pi radian/rev) x (1 minute/60 sec) = 2 pi X/60 = 0.10472 Xrad/sec (rounded)
The linear speed of the tire is given by v = ωr, where v is the linear speed, ω is the angular velocity, and r is the radius. Solving for ω, we get ω = v/r = 32.0m/s / 0.420m = 76.2 rad/s. To convert this to rev/min, we use the conversion factor 1 rev = 2π radians and 1 min = 60 s, so ω in rev/min = (76.2 rad/s * 60 s/min) / (2π rad/rev) ≈ 726 rev/min.
(550 - 200) rev per minute = -350 rev per minute / 60 sec per minute = (-35/6 rev per second) change in angular velocityAngular acceleration = (change in angular velocity) / (time for the change) =(-35/6 rev per second) x (2 pi radians per rev) / 4.5 seconds = -8.1449 radians per second2
For starter, 1 rad/S = 0.159 rev/S
The angular acceleration is 1.944... (repeating) rev per second^2.
(550 - 200) rev per minute = -350 rev per minute / 60 sec per minute = (-35/6 rev per second) change in angular velocityAngular acceleration = (change in angular velocity) / (time for the change) =(-35/6 rev per second) x (2 pi radians per rev) / 4.5 seconds = -8.1449 radians per second2("Meters per sec sq" can't be a unit of angularacceleration, since angles can't be measured in meters.)
Depends on the diameter of the wheels. Formula should be (5 min)*(60 sec/min)*(3 rev/sec)*(? meters/rev) Where ? meters would be the circumference of the wheels which is pi*diameter
The constant acceleration would be 0.0125 revolutions per second squared. This can be calculated by dividing the total number of revolutions by the square of the total time taken.
There are 60 sec in one min 35 rev/min x 45/60 = 26.25 revs
Rev par: revenue per available room (in hospitality parlance)
60 mph = 88 feet/sec = (88 x 12) inches per sec = (88 x 12 x 60) in/min = 63,360 inches per minuteCircumference of the wheel = 2 pi R = 30 pi inches.RPM = (63,360) / (30 pi) = 672.27 rev per min (rounded)
560 rpm The car is not revolving. If you want to know the engine rpm you would need to know the ratio of the differential (final drive) and the ratio of the gear that you are in. If you are asking for the number of revolutions per minute for the tire, you would calculate it as follows. Tire circumference is: 3.141 x 2.5 ft = 7.85 ft A revolution of the wheel would be 7.85 ft/rev so the reciprocal gives: a revolution is 0.1274 rev/ft. 50 mi/hr x 0.01667 hr/min x 5280 ft/mi = 4400 feet/min 0.1274 rev/ft x 4400 ft/min = 561 rev/min (or rpm) Note: Previously, the answer was rounded to 3 significant digits. If you consider that 50 mph is precise to the units place you can really only support two significant digits in the final answer so it needs to be rounded to 560 rpm.