Q: How can mental math be used to solve an equation?

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If you don't know something in a math equation you can replace it with a variable and then solve it algebraically.

The distributive property breaks down the equation to make it more simple to do. It is often used for mental math. An example is (12x56). (10x50=500)+(2x6=12) then, (500+12=512).

The answer to 744 times 31 equals 23064. To solve this math problem you will have to take the number 744 and add it 31 times.

For the most part it can. if you have a TI-83 or better, you can use the solver under your math button. All you have to do is plug in the equation that is set to equal zero!

It depends on the equation that is being solved.

Related questions

If you don't know something in a math equation you can replace it with a variable and then solve it algebraically.

The distributive property breaks down the equation to make it more simple to do. It is often used for mental math. An example is (12x56). (10x50=500)+(2x6=12) then, (500+12=512).

The answer to 744 times 31 equals 23064. To solve this math problem you will have to take the number 744 and add it 31 times.

The quadratic formula cannot be used to solve an equation if the coefficient of the equation's x2-term is 0.

For the most part it can. if you have a TI-83 or better, you can use the solver under your math button. All you have to do is plug in the equation that is set to equal zero!

The quadratic formula cannot be used to solve an equation if the coefficient of the equation x square term is what?

More than likely the first mental math used was during prehistory, as there was no written language or number system.

It depends on the equation that is being solved.

The number 3 equals x when it has the same value in an equation. This is used to help solve a specific problem in math where certain variables are unknown.

The quadratic formula can be used to solve an equation only if the highest degree in the equation is 2.

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It is used to solve quadratic equations that cannot be factored. Usually you would factor a quadratic equation, identify the critical values and solve, but when you cannot factor you utilize the quadratic equation.