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The quickest way, because 11 is odd, is as follows:Find two consecutive integers which add to 11.


From the origin, O, draw an arc of a circle with radius 6 units.

From the point 5, draw a vertical line to meet this arc an the point X.

You now have a right angled triangle O5X which has a right angle at 5.

By Pythagoras's Theorem,

OX^2 = O5^2 + 5X^2 => 6^2 = 5^2 + 5x^2

therefore 5X^2 = 6^2 - 5^2 = 36 - 25 = 11

and so 5X = sqrt(11)

So the length represented by 5X, the vertical line from 5 to the arc has a length = sqrt(11).

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