Q: How can you add the product of 7 and w to w?

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47. An equation for this would look like "x = 5 + 6*7" Using the order of operations (PEMDAS), you would find the product of 6*7, which is 42. Then, add 5 to get 47.

If you mean what numbers add to 10, whose product is 21, that would be 3 and 7.

Let w represent the width. The area of a rectangle equals the product of the length and width. From the statement of the problem, w(w + 7) = 60. Multiplying out the left side and rearranging gives w2 + 7w - 60 = 0. The number 60 can be factored into 12 X 5, which have a difference of 7. Therefore, this equation can be written as (w - 5)(w + 7), which is true when w has a value of 5 or -7. However, the length of a room can not be negative. Therefore, w is five and the width is 12, both in feet.

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You can add 50+6 and it equals 56

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fifty five

76

(7*7)+6=49+6=55

w/2 - 18 = - 7 Add 18 to both sides of the equation w/2 = - 7 + 18 w/2 = 11 Multiply both sides by 2 w = 11 x 2 w = 22

(7*8)+(7+8) = 56+15 = 71

(7 x 9) + 20 = 63 + 20 = 83

The product of w and 12 is 12w.

4. Reverse the process to find the number: 7 is added to the product of 3 and a number to get 19. The last thing done is add 7; the reverse process of add is subtract, so subtract 7, leaving: The product of 3 and a number is 19 - 7 = 12. The reverse process to multiply (product) by 3 is divide, so divide by 3, leaving: a number is 12 ÷ 3 = 4

You can't have the sum of one thing. Factors multiply to get a product. 7 x 9 = 63. If you add those two numbers, you will get a sum. 7 + 9 = 16

-3.8284 and 1.8284, approx.

You would add 9 to it.

It is: 7+w