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The exterior angles of any polygon add up to 360.

360/8 = 45

Q: How can you calculate the size of an exterior angle of a regular octagon?

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Each interior angle of an 8 sided regular octagon is 135 degrees and each exterior angle is 45 degrees

Each exterior angle of a regular octagon measures 45 degrees

Assuming you mean "what is the size of the exterior angle of a regular octagon", then: The sum of the exterior angles of any polygon is 360o. Thus for a regular octagon, each is 360o ÷ 8 = 45o.

45 degrees

Exterior angle: 45 degrees Interior angle: 135 degrees

Related questions

Each exterior angle of a regular octagon: 360/8 = 45 degrees

The external angle of a regular octagon is 225 degrees. Each internal angle of a regular octagon is 135 degrees.

Providing that it is a regular octagon each exterior angle measures 45 degrees.

An interior angle of a regular octagon is 45 degrees. The exterior angles measure 315 degrees.

Each exterior angle of a regular octagon is 360/8 = 45 degrees

Each interior angle of an 8 sided regular octagon is 135 degrees and each exterior angle is 45 degrees

Each exterior angle of a regular octagon measures 45 degrees

45 degrees providing that it is a regular octagon

45 degrees

45 degrees

Providing that it is a regular octagon: Exterior angle: 45 degrees Interior angle: 135 degrees

The exterior angle of a general octagon is any angle less than 180 degrees. The sum of the exterior angles of a polygon is 360 degrees. If the octagon is regular, then each of its 8 exterior angles is equal to 360/8 = 45 degrees.