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The answer depends on the level of your knowledge.

Suppose the base is of length b

and the vertical angle is x degrees.

Draw the base, AC, and its perpendicular bisector.

Calculate h = b/[2*tan(x/2)]. That is the height of the triangle so mark this point, B, on the perpendicular bisector.

Draw AB and BC.

Done!

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Q: How can you construct an isosceles triangle if only given the base and the vertical angle and the base angles can not be used for construction?
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An isosceles triangle has 1 vertical line of symmetry


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