It is the graph of a quadratic equation of the formy = ax^2 + bx + c
[ Ax + By = C ] If 'A', 'B', and 'C' are numbers, then the graph is always a straight line, and the equation is a "linear" one.
It is a straight line with gradient -A/B and intercept C/B.
Yes Ax + By = C As the line passes through the origin then x = 0 when y = 0. Substituting gives, 0 + 0 = C therefore C = 0.
y = (c - Ax) / (B)
ax + by = cThe graph if that equation is a straight line whose slope is (-a/b)and whose y-intercept is (c/b).
It is the graph of a quadratic equation of the formy = ax^2 + bx + c
A linear equation ?
False
[ Ax + By = C ] If 'A', 'B', and 'C' are numbers, then the graph is always a straight line, and the equation is a "linear" one.
I'm guessing that your equation is y = ax² + c (as there are limitations as to what punctuation, including mathematical symbols, can be put in a question). Increasing c by 4 units shifts the graph 4 units up the y-axis. If you equation was y = ax² - c, then increasing c by 4 units shifts the graph 4 units down the y-axis.
AX + BY is not an equation .AX + BY + C = 0is the general equation for a straight line.
It is a straight line with gradient -A/B and intercept C/B.
ax - b = c ax = b + c x = (b + c)/a
ax + by + cz + ... = k where x, y, z, etc are variables and a, b, c etc and k are constants. In the simple case of 2 variables, this becomes ax + by = k which can be rewritten as y = mx + c (different c from the first equation above).
Yes Ax + By = C As the line passes through the origin then x = 0 when y = 0. Substituting gives, 0 + 0 = C therefore C = 0.
ax+by=c