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Finding the speed of a projectile, such as, a ball is simple considering you know the net force acting on the ball. Another way to go about figuring out this problem would be knowing the exact distance it traveled, most likely a parabolic trajectory excluding air drag, and knowing the time the ball was in the air; then the speed of the ball would be given as D=rt(D denoting distance, r denoting average rate/speed, and t denoting the time the ball was in the air). Back to the first method the equation used in this circumstance would be F=ma, also know as Newton's Second law of motion, and would be easiest excluding air drag. So, a person throws a 145g/0.145kg ball with a force of .5 Newtons to go about finding the speed of the ball in this equation we would use the equation F=ma-.5=.145a-a=3.45m/s2 meaning all you have to do to find the speed of the ball is multiply the value by the number of seconds after the initial thrust. Therefor, .5 seconds after the toss the ball should be-- .5s(3.45m/s2) 3.45(.5)=1.725 and m/s2/s=m/s therefor the speed is 1.725m/s after half a second. Of course after the ball strikes the ground it will be influenced by another natural force imposed by the ground which should be equal to the force that the ball initially retained. Or taking air drag into effect the force would probably no longer have an influence on the balls speed and then be effected by the law of momentum conservation. As of now all we have is a speed for the ball, 1.725m/s, we also want a velocity. To derive a velocity all the information that is needed is to know which direction the force was directed in, lets say 14o North We would now write 1.725m/s 14oN which can be written as a vector.

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