You can get 55 by performing the following operations: First, multiply 7 by 12 to get 84. Then, subtract the product of 3 and 2, which is 6, from 84. This gives you 84 - 6 = 78, which is not correct.
A correct way to achieve 55 is: Multiply 7 by 12 to get 84, then subtract 3 and 2 multiplied together, which is 6. So, 84 - 6 = 78.
Sorry, it seems I made a mistake in calculation. There is no straightforward way to reach 55 using just the numbers 3, 7, 12, and 2 with basic operations.
55----------------------------------------------------------------------------------------------From Rafaelrz.You can make, 5! = 120, five digit numbers using 1,2,3,4 and 6.
There are 59C5 = 59*58*57*56*55/(5*4*3*2*1) = 5,006,386 combinations.
11 Proof; 22 / 11 = 2 55 / 11 = 5 If you try the same process with larger numbers (12-22) one of your answers will not be a whole number.
No, 2/12 is only one-fourth as large as 2/3.using 6, the LCD:2/12 = 1/6 (divide both numbers by 2)2/3 = 4/6 (multiply both numbers by 2)or using 12, the existing denominator2/12 = 2/122/3 = 8/12 (multiply both by 4)*if both numerators are the same (2), the larger fraction is the one with the smaller denominator (3, not 12).
No 5291 is not a prime using 2 numbers. It is a prime using three numbers.
2
2 x 2 x 3
Using the equation 55 x 2 = 110, the numbers are called as follows: multiplicand x multiplier = product.
To find a number between 55 and 65 that is divisible by 2, 3, 4, 5, 6, 10, and 12, we need to find the least common multiple (LCM) of these numbers. The LCM of 2, 3, 4, 5, 6, 10, and 12 is 60. Therefore, the number between 55 and 65 that is divisible by all these numbers is 60.
55----------------------------------------------------------------------------------------------From Rafaelrz.You can make, 5! = 120, five digit numbers using 1,2,3,4 and 6.
Well - 12-4 is 8 BUT assuming you have to use all the numbers... Add 12 to 4, then divide by 2 !
(5+7)*(5-3)=12*2=24
There are 59C5 = 59*58*57*56*55/(5*4*3*2*1) = 5,006,386 combinations.
You can make 4*3*2/2 = 12 numbers.
91/6 - 33/4 To calculate this we need to... convert both numbers to improper (or 'top-heavy') fractions to find the Lowest Common Multiple (LCM) of the two denominators re-calculate the two numbes using the LCM 91/6 ..... 6 x 9 = 54 ..... 54 + 1 = 55 ..... 91/6 = 55/6 33/4 ..... 3 x 4 = 12 ..... 12 + 3 = 15 .... 33/4 = 15/4 The factors of 6 are 2 and 3, and the factors of 4 are 2 and 2 - so the LCM must be 2 x 2 x 3 = 12 55/6 = 110/12 15/4 = 45/12 110 - 45 = 65 65/12 = 55/12
There are not 55. Only these: 1, 2, 3, 4, 6, 7, 8, 12, 14, 21, 24, 28, 42, 56, 84, 168.
5 * 55 = 275