Use the Hero's formula: Let s = (a + b + c)/2. Then the area of the triangle equals√[s(s - a)(s - b)(s - c)], where a, b, and c denote the sides of the triangle.
Let the sides be a, b, c Area = sq rt [s(s-a)(s-b)(s-c)] where s= 1/2 (a+b+c)
The answer depends on the information that you do have. Suppose you know all the edge lengths: the three sides of the triangle are a, b and c and the length of the prism is d. Let s = (a + b + c)/2 Then the area of the triangular cross section is sqrt[s*(s-a)*(s-b)*(s-c)] square units. So, surface area = 2*sqrt[s*(s-a)*(s-b)*(s-c)] + d*(a+b+c) square units. Volume = sqrt[s*(s-a)*(s-b)*(s-c)]*d cubic units.
Let A,B,C,D Four different sides with different lengths. Apply the following formula. A = Sqrt ( ( s-a) ( s-b) (s-c) (s-c) ) Where S = ( a+b+c+d) / 2.
120 sq metres. To see how you get this answer, read on: If the sides are a, b and c, then calculate s = 0.5*(a+b+c) Then the area is sqrt[s*(s-a)*(s-b)*(s-c)]
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Total marks are a way of grading a student in a class like B Tech Computer Science. These marks range from 0 to 100 with corresponding letter grades of S, A, B, C, D, E, and F.
Not normally. The person (s) for whom the memo' is intended is included at the beginning e.g. To: M. Boyle, Chemistry Dept. From: J. Smith, Headmaster
Not normally. The person (s) for whom the memo' is intended is included at the beginning e.g. To: M. Boyle, Chemistry Dept. From: J. Smith, Headmaster